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Finding a complex number from an equation

  1. Nov 12, 2013 #1
    1. The problem statement, all variables and given/known data

    Find all complex numbers z such that z^6 = -64

    2. Relevant equations

    I tried it in two ways, once with the sum of cubes (a + b)(a^2 - ab + b^2)
    as well as turning it into polar form and attempting it that way, z = re^(iθ)

    3. The attempt at a solution

    I completely couldn't solve it at all with the sum of cubes, however, I managed to get six solutions by using the polar form and then saying that θ = ∏/3 (3 + k), where k = 0, 1, 2, 3, 4, 5

    By subbing in k into the equation z = r(cosθ + isinθ), where r = 2, I get the answers: -2i, +-(-1 - sqrt(3)i), +- (1 + sqrt(3)i), and +2i. However, the book i'm using gives the answers +- 2i, and +- (sqrt(3) + i), and +- (-sqrt(3) - i). Thank you guys in advance.
     
  2. jcsd
  3. Nov 12, 2013 #2

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    Well, (-1 - sqrt(3)i)^6=64, not -64. Something clearly went wrong with your polar solution. Can you show us what you did?
     
  4. Nov 12, 2013 #3

    jedishrfu

    Staff: Mentor

    We used to solve these in a geometrically way noting that the roots will be on a circle equally spaced at every 60 degrees about 0+0i and with a radius of 2. So given one root you can find the others.
     
    Last edited: Nov 12, 2013
  5. Nov 12, 2013 #4
    Well, r^6 = 64 so r = 2, and then because a / r = - 32, and b / r = 0, I just assumed that the angle I start at is pi, so my angle equation becomes 6θ = ∏ + 2∏k, and oh wait I pretty much just found my error as soon as I typed it out LOL, thanks alot.
     
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