Finding a number that can divide evenly into another number?

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To find a number that can divide evenly into two given numbers, the greatest common divisor (GCD) is the correct term to use. Key methods to determine divisibility include recognizing that even numbers are divisible by 2, numbers ending in 0 or 5 are divisible by 5, and if the sum of a number's digits is divisible by 3, then the number itself is also divisible by 3. The discussion clarified the distinction between "greatest common denominator" and "least common denominator," emphasizing that the latter applies to fractions. The Euclidean algorithm is a commonly referenced method for calculating the GCD. Understanding these concepts can simplify the process of finding common divisors.
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when you have two numbers and you need find a number can can divide evenly into both is there an easy method to do this
 
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Are you thinking of the greatest common denominator?
 
jim1174 said:
when you have two numbers and you need find a number can can divide evenly into both is there an easy method to do this
There are some rules which can lessen the amount of work involved:
1. Even numbers are all evenly divisible by 2.
2. Numbers ending in 0 or 5 are also divisible by 5 or multiples of 5.
3. If the sum of the digits in a number can be divided evenly by 3, then the original number can also be divided by 3. For example, if n = 522, then 5 + 2 + 2 = 9, which is divisible by 3 evenly; therefore 522 is also evenly divisible by 3. (522/3 = 174)
 
jedishrfu said:
Are you thinking of the greatest common denominator?
Since there are no fractions involved here, you must mean "greatest common divisor". In fact there is no "greatest common denominator" for a set of fractions- there is the "least common denominator" which is a number into which all the denominators will divide.
 
HallsofIvy said:
Since there are no fractions involved here, you must mean "greatest common divisor". In fact there is no "greatest common denominator" for a set of fractions- there is the "least common denominator" which is a number into which all the denominators will divide.

Yes, you are right. I was thinking GCD and my memory brought up the wrong term. Thanks for the correction. I should have added a reference and then I would have caught my mistake.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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