Finding a Polynomial with Nonnegative Coefficients

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SUMMARY

The discussion focuses on finding a polynomial P(x) with nonnegative coefficients that satisfies the conditions P(1)=6 and P(5)=426. Participants conclude that the polynomial must be of at least degree 4, as lower-degree polynomials cannot meet the given conditions. The solution involves setting up equations based on the polynomial's coefficients and using linear algebra techniques to derive the coefficients. The final goal is to determine P(3) based on the established coefficients.

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chillfactor
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Homework Statement



find a polynomial P(x) which has nonnegative coefficients. If P(1)=1 and P(5)= 426, then wast is p(3)

Homework Equations


P(1)= 6
P(5)= 426
P(3)= x

The Attempt at a Solution


I have tried to use guess and check. I can't find a way to solve algebraically.
 
Last edited:
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Do you have a specified degree for p(x) ?
 
There is no specified degree for p(X). It just has to have nonnegative coefficents
 
chillfactor said:
There is no specified degree for p(X). It just has to have nonnegative coefficents

Then it is best to choose a degree and work with that.
 
There is only one polynomial that works. One hint I received was that it had to be less than 6.
 
I have no idea how to approach it either. Can't quite gather what to do with the fact that all the coefficients aren't negative. Either way, it must be at least a polynomial of degree 4. But what suggests that it must be less than 6?
 
how do you know it must be at least degree 4?
 
If you try to fit for example a quadratic

ax^2+bx+c to the conditions, then you get two conditions:

a+b+c=1

25a+5b+c=426

We can subtract one from the other to get

24a+4b=425

Now we know that a+b+c=1 must be satisfied, with all non-negative numbers, so none of a, b or c can be larger than 1. That's clearly not possible if 24a+4b=425. A similar argument kills cubic polynomials
 
i am afraid i made a mistake when I posted the question. Actually P(1)= 6. So, could you try again. I would appreciate it.
 
  • #10
There are lots of choices of polynomials actually, just consider a degree n polynomial of the form axn+b. We know that a+b=6, and that 5na+b=426. Two equations, two unknowns, start trying to find solutions!

If you know a little linear algebra/convex geometry there's a neat explanation for how you can decide exactly which coefficients are able to be non-zero
 
Last edited:
  • #11
welcome to pf!

hi chillfactor! welcome to pf! :wink:
chillfactor said:
find a polynomial P(x) which has nonnegative coefficients. If P(1)=6 and P(5)= 426, then wast is p(3)

i assume all the coefficients must be whole numbers?

then ∑an = 6 and ∑an5n = 426

obviously a0 = 1,

and by subtracting we have 4a1 + 24a2 + 124a3 = 420 …

carry on from there :smile:
 
  • #12


thanks!
 

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