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rustynail
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Hello, I am currently taking a college level chemistry class. I am struggling with this problem, any help would be greatly appreciated.
We have a certain quantity of
[tex] CuSO_{4} \cdot \gamma H_{2}O [/tex]
If our sample is formed of (25,5% Cu), (12% S), (57,7% O) and (4.04% H), what is the value of gamma ?
None given.
I have determined the mass of 1mol of each element, the mass of 1mol of CuSO_4 (111.611g) and really, I'm stuck there.
Please don't spoil the fun for me, just give me some hints.
(edit) : I have done this much more :
Mass of 1mol Cu = 63.546g
(63.546g/111.611g)*100 = 56.94% Cu in CuSO_4
56.94%/25.5% = 2.2328 (increment factor)
So the mass of the hydrated CuSO_4 should be
111.611g * 2,2328= 249.21g
249.21g - 111.611g = 137.6g H2O
and 137.6g/18(g/mol)= 7.6 mol H2O
but it does not give me an integer...
Homework Statement
We have a certain quantity of
[tex] CuSO_{4} \cdot \gamma H_{2}O [/tex]
If our sample is formed of (25,5% Cu), (12% S), (57,7% O) and (4.04% H), what is the value of gamma ?
Homework Equations
None given.
The Attempt at a Solution
I have determined the mass of 1mol of each element, the mass of 1mol of CuSO_4 (111.611g) and really, I'm stuck there.
Please don't spoil the fun for me, just give me some hints.
(edit) : I have done this much more :
Mass of 1mol Cu = 63.546g
(63.546g/111.611g)*100 = 56.94% Cu in CuSO_4
56.94%/25.5% = 2.2328 (increment factor)
So the mass of the hydrated CuSO_4 should be
111.611g * 2,2328= 249.21g
249.21g - 111.611g = 137.6g H2O
and 137.6g/18(g/mol)= 7.6 mol H2O
but it does not give me an integer...
Last edited: