- #1
Puchinita5
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Homework Statement
For the reaction N2(g) + 3H2(g) <---> 2NH3(g)
I am supposed to determine the equilibrium constant at 298K and 1 bar. We have been given a table that states that
for NH3(g):
[itex]\Delta_{r}G^{\Theta}= -16.45 kJ/mol[/itex]
I know that
[itex]\Delta_{r}G^{\Theta}= \Sigma v G^{\Theta}_{product} - \Sigma v G^{\Theta}_{reactant}[/itex]
where v is the stoichiometric coefficient.
But what is confusing me is that you could also write the equation as
1/2 N2(g) + (3/2)(g) <----> NH3(g)
so in the first case, the answer would be
(2*-16.45 kJ/mol) - ((1*0)+(3*0)) = -32.90 kJ/mol
But in the second case, the answer would be
(-16.45 kJ/mol) - (1/2*0 + 3/2 *0) = -16.45 kJ/mol
Since both equations should be valid, what answer is correct? I don't understand which one I should choose because they both look like the should be right.