Finding a vector field perpendicular to the surface of a sphere

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SUMMARY

To determine if a vector field is perpendicular to the surface of a sphere of radius R, the vector field must be expressed in spherical coordinates. The user initially attempted to use the cross product with the normal vector at the surface but found it complex. An alternative approach is to express the vector field as a scalar multiple of the radius vector, specifically in the form F = f(θ, φ)ρ, where f is a scalar function. This method simplifies the verification of perpendicularity without the complications of cross products.

PREREQUISITES
  • Spherical coordinates and their representation
  • Understanding of vector fields and their properties
  • Knowledge of normal vectors on surfaces
  • Basic vector calculus concepts
NEXT STEPS
  • Study the properties of vector fields in spherical coordinates
  • Learn about normal vectors and their applications on curved surfaces
  • Explore alternative methods for checking vector field perpendicularity
  • Investigate scalar functions and their role in vector field representation
USEFUL FOR

Mathematicians, physicists, and engineers working with vector fields, particularly those involved in fields such as fluid dynamics or electromagnetism, will benefit from this discussion.

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I'm trying to figure out if a given vector field is perpendicular at the surface of a sphere of radius R. The vector field is given in spherical coordinates.

I initially attempted to take the cross product of the vector field with the normal vector at the surface of the sphere to see if it was zero, but unfortunately, the cross product in spherical coordinates is much too difficult to work with. I'm hoping to find an alternative method.

Does anyone know how to find out if a vector field is perpendicular to a surface without using the cross product?
 
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At each point on the sphere the field would have to be a multiple of the radius vector. Something like

[tex]\vec F = f(\theta,\phi)\vec \rho[/tex]

where f is a scalar.
 
Thank you very much!
 

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