• Support PF! Buy your school textbooks, materials and every day products Here!

Finding Absolute Uncertainty

  • Thread starter Coop
  • Start date
  • #1
40
0

Homework Statement


Hello,

I have solved the problem, but not the way the writer intended. I need help figuring out how they wanted me to do it.

Here's the problem:

The circumference of a sphere is found to be 0.98 m +/- 0.01 m. Calculate the volume and absolute error with five digits to the right of the decimal.

Homework Equations


C = 2∏r
V = (4/3)∏r3


The Attempt at a Solution


I used the low end (.97 m) and high end (.99 m) circumference measurement to solve for two radii. Then I plugged those in to the volume equation and got to volume values: .01541 m3 and .01639 m3. Averaging those volumes I found the final volume to be .01589 m3.

To find the absolute uncertainty I merely subtracted the high end circumference value from the low end one and divided by two.

∴ volume = .01589 m3 +/- .00049 m3.

But my question is, they wanted me to find absolute uncertainty using the following formulas:

Δ[constant]X = [constant]*ΔX to account for constants
(Δtotal/final value) = |n| * [(ΔX)/X] to find uncertainty values where n is an exponent on A
ΔX = [(ΔX)/X] * X to convert from relative to absolute error

...where Δ stands for uncertainty

How would I do this?

It seems a lot more confusing for no reason, but would there be any case when I wouldn't be able to use my method and would have to use these formulas?

P.S. Is there anyway to code when writing these? Like I know for some help sites you can input fractions using commands like \frac{num.}{denom.}
 

Answers and Replies

  • #2
6,054
390
Coop said:
The circumference of a sphere is found to be 0.98 m +/- 0.01 m.
What does this even mean, "circumference of a sphere"?

As to your question, what exactly is unclear in the formulae given to you?

To see how to enter stuff like ##V = \frac 4 3 \pi r^3 ##, click the quote button.
 

Related Threads on Finding Absolute Uncertainty

  • Last Post
Replies
21
Views
3K
  • Last Post
Replies
1
Views
25K
  • Last Post
Replies
1
Views
4K
Replies
14
Views
4K
  • Last Post
Replies
0
Views
6K
  • Last Post
Replies
0
Views
3K
Replies
3
Views
4K
Replies
2
Views
3K
Replies
1
Views
3K
  • Last Post
Replies
1
Views
6K
Top