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Finding Absolute Uncertainty

  1. Aug 29, 2013 #1
    1. The problem statement, all variables and given/known data
    Hello,

    I have solved the problem, but not the way the writer intended. I need help figuring out how they wanted me to do it.

    Here's the problem:

    The circumference of a sphere is found to be 0.98 m +/- 0.01 m. Calculate the volume and absolute error with five digits to the right of the decimal.

    2. Relevant equations
    C = 2∏r
    V = (4/3)∏r3


    3. The attempt at a solution
    I used the low end (.97 m) and high end (.99 m) circumference measurement to solve for two radii. Then I plugged those in to the volume equation and got to volume values: .01541 m3 and .01639 m3. Averaging those volumes I found the final volume to be .01589 m3.

    To find the absolute uncertainty I merely subtracted the high end circumference value from the low end one and divided by two.

    ∴ volume = .01589 m3 +/- .00049 m3.

    But my question is, they wanted me to find absolute uncertainty using the following formulas:

    Δ[constant]X = [constant]*ΔX to account for constants
    (Δtotal/final value) = |n| * [(ΔX)/X] to find uncertainty values where n is an exponent on A
    ΔX = [(ΔX)/X] * X to convert from relative to absolute error

    ...where Δ stands for uncertainty

    How would I do this?

    It seems a lot more confusing for no reason, but would there be any case when I wouldn't be able to use my method and would have to use these formulas?

    P.S. Is there anyway to code when writing these? Like I know for some help sites you can input fractions using commands like \frac{num.}{denom.}
     
  2. jcsd
  3. Aug 29, 2013 #2
    What does this even mean, "circumference of a sphere"?

    As to your question, what exactly is unclear in the formulae given to you?

    To see how to enter stuff like ##V = \frac 4 3 \pi r^3 ##, click the quote button.
     
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