Finding Amplitude of the Oscillation

[Hydrous Caperilla]

Homework Statement

A
A man applies a Force F on a spring block system shown.towards right when the block is at rest and spring is relaxed .If F is constant then
[/B]

Homework Equations

: F=-kx[/B]

The Attempt at a Solution

The equilibrium position will be at the position where the disturbing and restoring fores are equal

F=kx
x=F/k

Also the time period will be 2pi√m/k.How should I proceed after this

 

[NFuller]

What is the problem asking you to find?

 

[Hydrous Caperilla]

What is the problem asking you to find?

The Amplitude of the resulting simple harmonic motion

 

[ehild]

Homework Statement

A
A man applies a Force F on a spring block system shown.towards right when the block is at rest and spring is relaxed .If F is constant then
[/B]

Homework Equations

: F=-kx[/B]

The Attempt at a Solution

The equilibrium position will be at the position where the disturbing and restoring fores are equal

F=kx
x=F/k

Also the time period will be 2pi√m/k.How should I proceed after this

What is the initial position of the block with rspect to the new equilibrium point?

 

[Hydrous Caperilla]

What is the initial position of the block with rspect to the new equilibrium point?

What is the initial position of the block with rspect to the new equilibrium point?

The intial position of the block is at the point where the spring is relaxed

 

[NFuller]

If the force applied is constant, as stated, then the equilibrium position is where the applied force $F_{a}$ is equal to the force from the spring $F_{s}$.
$F_{a}=F_{s}=kx$
You just need to solve for $x$.

 

[ehild]

The intial position of the block is at the point where the spring is relaxed

Yes, and it will perform SHM about the new equilibrium point. At t=0, what is its displacement with respect to that point?

 

[Hydrous Caperilla]

If the force applied is constant, as stated, then the equilibrium position is where the applied force $F_{a}$ is equal to the force from the spring $F_{s}$.
$F_{a}=F_{s}=kx$
You just need to solve for $x$.

I got the new equilibrium point from that...I am confused about how to proceed after that

 

[Hydrous Caperilla]

Yes, and it will perform SHM about the new equilibrium point. At t=0, what is its displacement with respect to that point?

F/k in my opinion

 

[ehild]

F/k in my opinion

Yes. Write the time dependence of the displacement of the box for t ≥ 0.

 

[NFuller]

I got the new equilibrium point from that...I am confused about how to proceed after that

If the problem is asking for the SHM about this new equilibrium point, then you need to know something about the velocity of the block at that point. It seems like your post is missing half of the problem.

 

[ehild]

If the problem is asking for the SHM about this new equilibrium point, then you need to know something about the velocity of the block at that point. It seems like your post is missing half of the problem.

The block is at rest and the spring is relaxed initially. So you know the position and velocity at t =0. No need for the velocity at the new equilibrium.

 

[Hydrous Caperilla]

Yes. Write the time dependence of the displacement of the box for t ≥ 0.

The equation of displacement will be :X=Asin( ωt+ Φ). At t=0, F/k=Asin( Φ).

 

[Hydrous Caperilla]

The block is at rest and the spring is relaxed initially. So you know the position and velocity at t =0. No need for the velocity at the new equilibrium.

You said the block is at rest at this point...won't this mean this is the amplitude point because at amplitude velocity is zero?

 

[ehild]

You said the block is at rest at this point...won't this mean this is the amplitude point because at amplitude velocity is zero?

Yes, the displacement of the block from its new equilibrium is biggest at t=0, when it is in rest. And the biggest displacement from equilibrium is the amplitude.