Finding an angle of a projectile for a specific distance

[trexmatt]

Homework Statement

A fire hose held near the ground shoots water at a speed of 6.5 m/s. At what angle(s) should the nozzle point in order that the water land 2.0m away. Why are there two different angles?

Homework Equations

v=v0 +at v^2=v0^2 +2ad d=V0t+1/2at^2

The Attempt at a Solution

I'm not sure how to go about solving this. I've gotten as far as this (calling the angle x)

Vy = Vosinx and Vx = Vocosx

Any help would be much appreciated, I don't understand where to go from here. It seems like none of the equations are going to go anywhere.

Thank you very much for your time...

 

[tiny-tim]

Welcome to PF!

Hi trexmatt ! Welcome to PF!

(have a theta: θ and try using the X² tag just above the Reply box )

v=v0 +at v^2=v0^2 +2ad d=V0t+1/2at^2
…
Vy = Vosinx and Vx = Vocosx

Yes, those are the equations to use

(except don't use x for two different things! )

Now treat the x and y directions separately (a = -g for y, a = 0 for x), to get a pair of equations involving θ, from which you can then eliminate t.