A projectile was launched from the top of a 100m tower upward at an angle theta to the horizontal with an initial velocity of 36m/s. The time of flight of the projectile was 8 seconds.
i) The angle of projection
ii) The maximum height reached by the projectile
The Attempt at a Solution
I am used to solving these questions when i am not given time but given both the horizontal and vertical distances. At which I use the quadratic formula to solve for theta. However in this case I can not do that as when i split my horizontal and vertical components and apply the above equations I am left with these.
I have tried rearranging the vertical formulas to solve for theta
301.42 = 36*sin(?)
sin-1(36/301.42) = 6.85 degrees
I really don't think that the answer is correct. The lecture who set the question will not give any answers.