1. The problem statement, all variables and given/known data A projectile was launched from the top of a 100m tower upward at an angle theta to the horizontal with an initial velocity of 36m/s. The time of flight of the projectile was 8 seconds. Determine: i) The angle of projection ii) The maximum height reached by the projectile 2. Relevant equations S=ut+1/2at^2 3. The attempt at a solution I am used to solving these questions when i am not given time but given both the horizontal and vertical distances. At which I use the quadratic formula to solve for theta. However in this case I can not do that as when i split my horizontal and vertical components and apply the above equations I am left with these. Horizontally S=36cos(?)*8 Vertically -100=36sin(?)*8+0.5*-9.81*64 I have tried rearranging the vertical formulas to solve for theta -1/2*-9.81*64-100/8=36sin(?) 301.42 = 36*sin(?) sin-1(36/301.42) = 6.85 degrees I really don't think that the answer is correct. The lecture who set the question will not give any answers.