Finding an Indeterminate Limit with L'Hôpital's Rule: Help and Explanation

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Discussion Overview

The discussion revolves around finding the limit of the expression lim x → ∞ ( x rx ) for r < 1, which is presented as an indeterminate form. Participants explore the application of L'Hôpital's rule to resolve this limit, discussing the challenges encountered in the process.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in finding the limit, identifying it as an indeterminate form of ∞ * 0 and attempting to apply L'Hôpital's rule.
  • Another participant suggests an alternative approach using the expression lim x → ∞ (x/(1/r)x) to apply L'Hôpital's rule.
  • A subsequent reply questions whether the suggested approach results in an indeterminate form of ∞ / ∞, noting that L'Hôpital's rule is typically applied to 0 / 0 forms.
  • Another participant clarifies that L'Hôpital's rule can also be applied to forms of ±∞/∞, challenging the previous assertion about its applicability.

Areas of Agreement / Disagreement

Participants generally agree on the use of L'Hôpital's rule but disagree on the conditions under which it can be applied, particularly regarding the forms of indeterminacy.

Contextual Notes

The discussion highlights potential misunderstandings regarding the application of L'Hôpital's rule and the nature of indeterminate forms, but does not resolve these issues.

swampwiz
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I can't seem to figure out how to find this seemingly simple limit (that is shown numerically to go to 0)

lim x → ∞ ( x rx )

for r < 1

This is an indeterminate form of ∞ * 0, but when I try to apply L'Hôpital's rule as

lim x → ∞ ( rx / ( 1 / x ) )

I end up getting an expression of the form x2 rx, with further application of the rule generating higher and higher powers of x

I'm totally stuck!
 
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You have the right idea. Try this instead:

lim x → ∞ (x/(1/r)x)
 
gb7nash said:
You have the right idea. Try this instead:

lim x → ∞ (x/(1/r)x)

But wouldn't that be ∞ / ∞ ? L'Hopital's rule only applies to 0 / 0
 
swampwiz said:
L'Hopital's rule only applies to 0 / 0

No it doesn't. It also applies to +- inf/inf
 

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