Finding an objects surrounding temperature

  • Thread starter Xek_0003ad64
  • Start date
  • Tags
    Temperature
In summary: T0 = (303^4 - 155/(.9*5.67x10^-8*1.5)^-4T0 = 290 KIn summary, you can solve for an object's surrounding temperature (T0) using the equation P=εσA(T^4-T0^4) when given the values for A, T, σ, and P. By rearranging the equation, you can find T0 to be 290 K in this particular scenario.
  • #1
Xek_0003ad64
1
0

Homework Statement



Hi, I have just started with physics and this is my first time posting on this forum, The question is very confusing. it asks:
What is an objects surrounding temperature (T0) if we know the:
A=1.5
T=303 K
σ=5.67x10^-8
ε=.9
P (net radiated power gained)= 155 W

See attachment, question 3(c)

Homework Equations



either;
P=εσA(T^4-T0^4) or εσAT^4

The Attempt at a Solution



I have not made an attempt, the answer of the first equation requires both surrounding temperature (T0) and the temperature of the object (T) but the answer would be the rate at which an object radiates energy; in joules, not watts (from what I understand) but the other equation doesn't have the T0, so you can't use algebra to solve it.
Please don't just type the answer, explain how you got it.

Thanks.
 

Attachments

  • Untitled.png
    Untitled.png
    13.6 KB · Views: 431
Physics news on Phys.org
  • #2
You appear to have all the info needed to solve your equation for T0 using..

P=εσA(T^4-T0^4)

where P is in Watts. One Watt = one Joule per second.

P=εσAT^4 - εσAT0^4

εσAT0^4 = εσAT^4 - P

T0^4 = T^4 - P/εσA

T0 = (T^4 - P/εσA)^-4

Substitute..
A=1.5
T=303 K
σ=5.67x10^-8
ε=.9
P (net radiated power gained) = 155 W = 155 J/S
 

Related to Finding an objects surrounding temperature

1. What is the purpose of finding an object's surrounding temperature?

The purpose of finding an object's surrounding temperature is to understand its thermal environment, which can provide valuable information about its physical properties and behavior.

2. How do scientists measure an object's surrounding temperature?

Scientists typically use thermometers or infrared cameras to measure an object's surrounding temperature. Thermometers measure the temperature of an object's surface, while infrared cameras can capture temperature readings from a distance.

3. What factors can affect an object's surrounding temperature?

An object's surrounding temperature can be affected by various factors such as sunlight, air temperature, humidity, and the material and color of the object's surface. Other factors may include the object's proximity to other heat sources and its own internal heat production.

4. Why is it important to take multiple temperature readings around an object?

It is important to take multiple temperature readings around an object because temperature can vary across an object's surface. By taking multiple readings, scientists can get a more accurate understanding of the object's surrounding temperature and potential temperature gradients.

5. How can an object's surrounding temperature impact its function or behavior?

An object's surrounding temperature can impact its function or behavior in various ways. For example, extreme temperatures can cause materials to expand or contract, affecting the object's shape and structure. Temperature can also affect the chemical reactions and physical processes that occur within an object, ultimately influencing its behavior and performance.

Similar threads

  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
2
Replies
41
Views
4K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
619
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
953
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
894
  • Introductory Physics Homework Help
Replies
1
Views
1K
Back
Top