Finding Analyticity Region of a Function - Matt

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SUMMARY

This discussion focuses on determining the analyticity region of complex functions, specifically the logarithmic functions Log z and Log z². It is established that Log z is analytic on the entire complex plane except for the negative real axis, while Log z² is analytic everywhere except at z=0 and along the imaginary axis. The conversation also highlights the concept of analytic continuation as a method to understand the regions of analyticity for more complex functions like Log(1+2/z).

PREREQUISITES
  • Understanding of complex functions and their differentiability
  • Familiarity with the properties of logarithmic functions in complex analysis
  • Knowledge of the concept of analyticity in the context of complex variables
  • Basic grasp of analytic continuation and its implications
NEXT STEPS
  • Research the concept of analytic continuation in complex analysis
  • Study the properties of the complex logarithm and its branches
  • Learn about the Cauchy-Riemann equations and their role in determining analyticity
  • Explore advanced topics in complex analysis, such as Riemann surfaces
USEFUL FOR

Students and professionals in mathematics, particularly those studying complex analysis, as well as anyone interested in understanding the properties of analytic functions and their regions of definition.

ultramat
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Hi, I have some questions regarding how to find the analytisity region of a funtion.
I'm a little confuse after I studied the definition of analytic function: which it saids
[if a function f is differentiable at every z in A, then f is analytic on A]

eg. Log z is analytic on the entire complex plane EXCEPT the -ve real axis.
Which make sense to me since Log z is undefind when x<=0 & y=0 , for z=x+iy

Log z^2 is analytic on the entire complex plane again EXCEPT z=0, and exclude the
Imaginary axis. Is that right?

I'm wondering if there's a way to actually compute/calculate the region instead of doing it in the head?
Since Log z & Log z^2 is kinda basic, it'll be hard to do if it is comething like Log (1+2/z)

Thanks in advance

Matt
 
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log(-1) CAN be defined since e^(i*pi)=-1. The upper case 'L' in Log is not is not just ornamental. It's a branch of log that's undefined for negative reals precisely so it can be uniquely defined for all other complex numbers. You can't compute why a function like that is undefined. Where it's undefined is a matter of convention. Look up "analytic continuation".
 

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