MHB Finding Angle C in Triangle ABC

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In triangle ABC, with angle B measuring 30 degrees, the relationship between the sides is given by the equation BC² - AB² = AB × AC. To find angle C, one can apply the Law of Cosines or manipulate the given equation. The problem requires solving for angle C based on the established conditions. The solution involves using trigonometric identities or geometric properties to derive the angle. Ultimately, the goal is to determine the measure of angle C accurately.
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$\triangle ABC,\angle B=30^o , \,\,and \,\, \overline{BC}^2 - \overline{AB}^2=\overline{AB}\times \overline{AC}\\
find \,\, \angle C=?$
 
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Albert said:
$\triangle ABC,\angle B=30^o , \,\,and \,\, \overline{BC}^2 - \overline{AB}^2=\overline{AB}\times \overline{AC}\\
find \,\, \angle C=?$
hint
prove $\angle A=2\angle C$
 
Albert said:
$\triangle ABC,\angle B=30^o , \,\,and \,\, \overline{BC}^2 - \overline{AB}^2=\overline{AB}\times \overline{AC}---(1)\\
find \,\, \angle C=?$
more hint:
in fact $\angle B=30^o$ is not important, you should prove for any triangle if $\angle A=2\angle C $ then (1) will meet
 
Albert said:
more hint:
in fact $\angle B=30^o$ is not important, you should prove for any triangle if $\angle A=2\angle C $ then (1) will meet
my solution :
 

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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