Finding angular speed/accel from tangential speed

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SUMMARY

The discussion focuses on calculating the angular speed and average angular acceleration of a take-up reel in a reel-to-reel tape deck, where the tape moves at a constant linear speed of 0.381 m/s. The key equations used are Vtangential = r * omega and accelerationtangential = r * alpha. The challenge arises from the variable radius (r) due to the tape's reeling effect, which complicates the calculations. Participants emphasize the need to determine the radius to solve for angular speed (omega) and angular acceleration (alpha).

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Homework Statement



Professional recording studios often use reel-to-reel tape decks. On such a tape deck, the tape is pulled past the playback head at a constant linear speed of 0.381 m/s. (a) Using the data in part a of the figure, find the angular speed of the take-up reel. (b) After 2.79 x 10^3 s, the take-up reel is almost full, as part b of the drawing indicates. Find the average angular acceleration of the reel with the appropriate sign, where a positive value means the reel is speeding up.


Homework Equations



Vtangential = r*omega (which here will be w)
accelerationtangential = r*alpha (here,alp)


The Attempt at a Solution


.381 m/s = r * w rad/s

In the diagram, r isn't given. Is there a way I can find it? It's constantly changing because of the tape's reeling effect, so I'm not sure how that would fit in.
 

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thatgirlyouknow said:
In the diagram, r isn't given
making the question unsolvable.
 

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