Please post the full problem so that we can see what data you have available.Cacti said:Homework Statement: Calculate the average acceleration for each member over the first 10.0 m.
Homework Equations: None given
I calculated the average velocity in a previous problem and got 1.146788991m/s over a time of 8.72s. I know I can’t use a_ave=(Vf-Vi)/(Tf-Ti) because I don’t know the final velocity and have no way to find it. Do I multiply average velocity by time?
Not if you are looking for something that has dimensions of acceleration.Cacti said:Do I multiply average velocity by time?
Cacti said:Homework Statement: Calculate the average acceleration for each member over the first 10.0 m.
Homework Equations: None given
I calculated the average velocity in a previous problem and got 1.146788991m/s over a time of 8.72s. I know I can’t use a_ave=(Vf-Vi)/(Tf-Ti) because I don’t know the final velocity and have no way to find it. Do I multiply average velocity by time?
The formula for average acceleration is: a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time interval.
The units for average acceleration are meters per second squared (m/s^2). This can also be written as m/s/s or simply m/s^2.
Yes, average acceleration can be negative. This indicates that the object is decelerating or slowing down.
Average acceleration is calculated over a specific time interval, while instantaneous acceleration is calculated at a specific moment in time. Average acceleration gives an overall picture of how an object's velocity changes over time, while instantaneous acceleration shows how an object's velocity is changing at that specific instant.
No, average acceleration is a measure of how an object's velocity changes over time, not its speed. To determine an object's speed, you would need to use the formula v = d/t, where v is the speed, d is the distance traveled, and t is the time interval.