Finding Average <x> for Probability Densities

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Homework Help Overview

The discussion revolves around finding the average value of for a given probability density function, specifically P(x) = A[a^{4}+(x-x_{0})^{4})]^{-1}. Participants are exploring concepts related to probability densities and normalization within the context of quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the integration methods for calculating the average value and normalization of the probability density function. There are differing opinions on whether to square the probability density in the normalization process and the appropriate intervals for integration.

Discussion Status

The discussion is active with various approaches being explored. Some participants have provided guidance on normalization and integration techniques, while others are questioning the necessity of certain steps in the process. There is no explicit consensus on the best method to proceed.

Contextual Notes

There are mentions of normalization requirements and the potential use of infinite intervals for integration, which may affect the determination of the constant "A".

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Homework Statement



What is the average <x> for following probability densities

P(x) = A[a[tex]^{4}+(x-x_{0})^{4})]^{-1}[/tex]


Homework Equations





The Attempt at a Solution



dont know how to start
 
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use this integration
[tex]\int_{a}^{b}\left|P(x)\right|^{2}*x*dx[/tex]
in the given interval [a,b]
At least, we're doing so in quantum meachanics
 
I forgot to say that you must normalize this function ie
[tex]\int_{a}^{b}\left|P(x)\right|^{2}*dx=1[/tex]
if the interval is not given you'll probably use [tex][-\infty,\infty][/tex].
So that you can determine the constant "A".
 
Hi!

I think you don't need to take the square of P(x) because he's already probability density.

You normalize the probability density to find A:

[tex]$ \int_{-\infty}^{\infty}P(x)dx = 1 $[/tex]

And then, the mean value of x ( <x> ) is:

[tex]$ \int_{-\infty}^{\infty}P(x)x dx $[/tex]
 
Last edited:

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