- #1
cookiesyum
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Homework Statement
Let X1 X2 X3 and X4 be four independent random variables, each with pdf f(x) = 3(1-x)2, 0<x<1, zero elsewhere. If Y is the minimum of these four variables, find the cdf and pdf of Y.
The Attempt at a Solution
P(Y<or= y)
= 1 - P(Y>y)
= 1 - P(X1>y, X2>y, X3>y, X4>y)
= 1 - P(X1>y)P(X2>y)P(X3>y)P(X4>y)
= 1 - [3(1-x)2]4
which does NOT equal (1-y)12, which is the answer in the back of the book. Don't know where I'm going wrong...