Finding Center and Radius of a Sphere

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To find the center and radius of a sphere defined by the distances from point P to points A and B, start by establishing the distances |PA| and |PB| using the distance formula. Given that |PA| is twice |PB|, set up the equation |PA| = 2|PB| and substitute the distance expressions for P to A (-1, 5, 3) and P to B (6, 2, -2). Squaring both sides simplifies the equation, allowing for further manipulation to reveal the sphere's equation. The resulting equation can then be analyzed to determine the center and radius of the sphere. This approach effectively demonstrates that the locus of points P forms a sphere.
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Homework Statement


If distance |AB| = root 83, and i also know that |PA| is twice |PB|, then how do you find? |PA| or |PB| ?

The whole question states: consider the points P such that the distance from P to A (-1,5,3) is twice the distance from P to B (6,2,-2).
Show that the set of all such points is a sphere, and find its center and radius.
please help!



Homework Equations





The Attempt at a Solution

 
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Let P=(x,y,z) and then the vector PB would be (6-x,2-y,-2-z)
Similarly, do with A...then use the fact that |PA|=2|PB|
 
Do you know the distance formula? Let P be the general point (x,y,z). Then the distance from P to (-1, 5, 3) is \sqrt{(x+1)^2+ (y-5)^2+ (z-3)^2} and the distance from P to (6, 2, -2) is \sqrt{(x- 6)^2+ (y-2)^2+ (z+2)^3}. Those are the |PA| and |PB| rock.freak667 is talking about. Put them into the equation he gives and simplify (I would square both sides).
 

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