Finding the Center and Radius of a Sphere with Parallel Tangent Planes

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The discussion focuses on determining the center and radius of a sphere defined by two parallel tangent planes, specifically x+2y-2z=37 and x+2y-2z=-11. The point of tangency provided is (-7,5,7), which lies on the plane x+2y-2z=-11. The distance from this point to the plane is calculated to be 16, establishing the sphere's radius as 8. The center of the sphere is located 8 units in the direction of the normal vector from the point of tangency towards the other plane.

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A sphere has two parallel tangent planes with equations x+2y-2z=37 and x+2y-2z=-11. One of the points of tangency is (-7,5,7). Find the center and radius of the sphere.


I'm not really sure how to do this. I know that the point (-7,5,7) lies on the x+2y-2z=-11 plane. The distance from the point to the plane using the distance formula is 16. So now I know that the sphere's diameter is 16, making the radius 8.

Can someone explain how to find the center of the sphere?

Thanks!
 
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That's good so far. Now find the normal direction of the planes. That means the center of the sphere lies 8 units in the direction of the normal from (-7,5,7) towards the other plane.
 

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