Finding center of gravity with a cut out

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SUMMARY

The discussion focuses on calculating the center of gravity for a 4.00 ft by 8.00 ft uniform sheet of plywood with a 3.50 ft by 2.10 ft cutout in the upper right quadrant. Participants emphasize the importance of using the center of mass position formula, specifically Āy = A₁y₁ + A₂y₂ + A₃y₃... and Āx = A₁x₁ + A₂x₂ + A₃x₃... for accurate calculations. The method involves splitting the shape into smaller rectangles and considering the cutout as a negative area. Correct application of these formulas is crucial for determining the correct coordinates of the center of gravity.

PREREQUISITES
  • Understanding of center of mass and centroid concepts
  • Familiarity with area calculations for geometric shapes
  • Knowledge of coordinate systems and reference axes
  • Ability to apply mathematical formulas for composite shapes
NEXT STEPS
  • Study the application of the center of mass formulas in composite shapes
  • Learn about negative area concepts in geometry
  • Explore methods for calculating centroids of irregular shapes
  • Practice with similar problems involving cutouts and composite areas
USEFUL FOR

Students in physics or engineering courses, educators teaching mechanics, and anyone involved in structural design or material analysis will benefit from this discussion.

mandy9008
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Homework Statement


Find the x- and y-coordinates of the center of gravity of a 4.00 ft by 8.00 ft uniform sheet of plywood with the upper right quadrant removed as shown in the figure below. The dimensions of the cutout are a = 3.50 ft and b = 2.10 ft.

p8-11alt.gif


The Attempt at a Solution


I made 2 squares out of this.
The left square: 4.5 x 4 having a center point of (2.25, 2).
The right square: 3.5 x 1.9 having a center point of (1.75, .95)
I then subtracted these coordinates (2.25, 2) - (1.75, .95) = (.5, 1.05)
This is wrong.
 
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You forgot to apply the center of mass's position formula when adding the coordinates:rolleyes:
What is the formula? :smile:
 
Do you know the formulas

A \bar{y} = A_1 y_1 + A_2y_2 + A_3y_3+...

A \bar{x} = A_1 x_1 + A_2x_2 + A_3x_3+...

Split the shape into squares or rectangles. The An terms are the areas of the different sections and the xn terms are the distance of the centroid of the sections from the reference axis.

So choose the y-axis as a reference and apply the formula.

Alternatively, you can consider it as one entire big rectangle and the part where the hole is would have negative area.
 
Last edited:

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