Finding change in height of fluid in U tube from change in T

AI Thread Summary
The discussion revolves around calculating the change in height of fluid in a U-tube due to temperature changes, with a focus on the relationship between pressure and temperature. Participants clarify that while pressure change is proportional to temperature change, they emphasize that proportionality does not imply numerical equality, especially when dealing with different units. The conversation also touches on the need for initial pressure and temperature values to calculate changes accurately using the ideal gas law. Questions arise about the implications of starting pressure and the assumptions of a true vacuum in the context of the calculations. The thread highlights the complexities of thermodynamic relationships and the importance of understanding the variables involved in such calculations.
JoeyBob
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Homework Statement
See attached
Relevant Equations
change P = (change h)*g*density
So first I converted the density from g/cm^3 to kg/cm^3 (it wants the answer in cm). This gives me a density of 0.01356 kg/cm^3.

Then I thought about the relationship of pressure and temperature. Since volume remains constant and temperature is the only variable changing, the change in pressure should be proportional to the change in temperature. A change in 56.3 degrees therefore should be a change in 56.3 pascals.

Now when I plug the numbers in, change in h=56.3/(9.8*0.01356) I get the incorrect answer of 423.67 cm. The correct answer is 21.31, which is not just off from unit conversions.
 

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JoeyBob said:
the change in pressure should be proportional to the change in temperature. A change in 56.3 degrees therefore should be a change in 56.3 pascals.
Proportional doesn't mean numerically equal to, especially when they are of different dimension. If you were working in Fahrenheit would a change of 56.3 degrees also mean a change of 56.3Pa?
The absolute temperature is proportional to the pressure: P/T is constant.
 
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haruspex said:
Proportional doesn't mean numerically equal to, especially when they are of different dimension. If you were working in Fahrenheit would a change of 56.3 degrees also mean a change of 56.3Pa?
The absolute temperature is proportional to the pressure: P/T is constant.
That makes sense. But then how would I calculate change in pressure if all I know from PV=nRT is initial temperature and final temperature?
 
JoeyBob said:
That makes sense. But then how would I calculate change in pressure if all I know from PV=nRT is initial temperature and final temperature?
... and initial pressure.
 
haruspex said:
... and initial pressure.
Where? Even if I had pressure, I still wouldn't have the moles nor volume. I just know what's constant.
 
JoeyBob said:
Where?
what is h initially?
 
haruspex said:
what is h initially?

0. But it doesn't make sense that pressure would be 0 to me. True vacuums don't exist.
 
JoeyBob said:
0. But it doesn't make sense that pressure would be 0 to me. True vacuums don't exist.
It doesn’t mean the pressure is zero.. unless the entire apparatus is in outer space.
 
haruspex said:
It doesn’t mean the pressure is zero.. unless the entire apparatus is in outer space.

Do I use the equation P(h)=P_0+density*g*h?
 
  • #10
JoeyBob said:
Do I use the equation P(h)=P_0+density*g*h?
Say what you think. Does it apply here? If so, what are P(0), P(h) etc. in this context?
 
  • #11
If h is zero to start with, and the outside pressure is 1 atm, what is the starting pressure inside the gas reservoir?
 
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