- #1

JoeyBob

- 256

- 29

- Homework Statement:
- see attached

- Relevant Equations:
- P=phg

The answer is suppose to be 0.9432. Initially I thought the pressure inside the glass ball would just be the same as the atmospheric pressure because these equal pressures would cancel each other out, but obviously that's not true.

I can calculate the density of the gas using the equation p1/p2=h2/h1, and get a density of 1659.8361. Now I thought I could calculate the pressure of the gas using P=pgh, where p is density, g gravity, h height of liquid. Using the height of the liquid on the gas side (0.244 m) I get 3968.9 which isn't the right answer. If I take the diffirence in height (0.169 m) I get a pressure of 2749.021. I tried subtracting this from the atmospheric pressure, because maybe the difference in height gives the difference in pressure, but this also gives the wrong answer.

The information about moles is useless because I don't know the temperature of the gas. Otherwise the question would be easy.

I can calculate the density of the gas using the equation p1/p2=h2/h1, and get a density of 1659.8361. Now I thought I could calculate the pressure of the gas using P=pgh, where p is density, g gravity, h height of liquid. Using the height of the liquid on the gas side (0.244 m) I get 3968.9 which isn't the right answer. If I take the diffirence in height (0.169 m) I get a pressure of 2749.021. I tried subtracting this from the atmospheric pressure, because maybe the difference in height gives the difference in pressure, but this also gives the wrong answer.

The information about moles is useless because I don't know the temperature of the gas. Otherwise the question would be easy.