Finding charge of insulating sphere and conductor

[phanman]

Homework Statement

For the configuration shown in the figure below, suppose that a = 6.10 cm, b = 21.6 cm, and c = 26.6 cm. Furthermore, suppose that the electric field at a point 11.5 cm from the center is 3.37x10^3 N/C radially inward, while the electric field at a point 58.6 cm from the center is 1.30x10^2 N/C radially outward.I can't copy picture so i will describe it. In the middle there is a sphere with radius a, it is an insulator. There is an outer ring around this sphere which has radius b. Than the last ring is the outermost ring with radius c. The last ring is a conductor.

(a) find the charge of the insulating sphere
(b) the net charge on the hollow conducting sphere.

Homework Equations

k_e(Coloumb constant) = 8.99 x 10^9 Nm^2/C^2
k_e(q/r^2)

The Attempt at a Solution

What i did was since the second ring there is an electric field of 3.37x10^3N/C which is given, i calculated q using the equation about. Than the innermost sphere charge should be the opposite of that.

 

[kuruman]

Hi phanman, welcome to PF.

There is no configuration "shown below." Without it, we cannot help you.