Finding Coefficient of Kinetic Friction for a Horizontal Force on a Wooden Desk

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Homework Help Overview

The discussion revolves around determining the coefficient of kinetic friction for a block being pulled across a wooden desk with a specified horizontal force and mass. The problem is situated within the context of friction and forces in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate the net force to the applied force and friction, questioning the correctness of their reasoning. Participants discuss the need for a formula connecting frictional force to the coefficient of friction.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on relevant formulas. There is a clear exchange of ideas, but no consensus has been reached regarding the final solution.

Contextual Notes

There is an indication that the original poster may have assumed the answer without fully exploring the relationship between the forces involved. The discussion reflects an ongoing exploration of the concepts rather than a resolution.

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Homework Statement


A horizontal force of 50 N is required to pull and 8.0 kg block at a unifrom velocity across a horizontal wooden desk. Determine the coefficient of kinetic friction.


Homework Equations


F_{Net}=ma


The Attempt at a Solution


I put F_{Net} as 0, because acceleration is 0. By doing this, I get the applied force and the force of friction both as 50, but I don't think that its right. By the way, the answer to the question is 0.64.
 
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You are correct in finding that the force applied is equal to the kinetic friction, but you need another formula to relate the frictional force to the coefficient of friction.
 
What would that formula be?
 
Friction Force = (Coefficient of friction)*(Normal force)
 
Thanks for the formula, I got the answer.:smile:
 

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