rock.freak667 Homework Helper Messages 6,221 Reaction score 31 Oct 28, 2013 #34 ughschool said: -cosθ x m x a / sinθ = Uk? No. This is your equation -mgsinθ + mμkgcosθ = -ma Solve for 'a'.
ughschool said: -cosθ x m x a / sinθ = Uk? No. This is your equation -mgsinθ + mμkgcosθ = -ma Solve for 'a'.
rock.freak667 Homework Helper Messages 6,221 Reaction score 31 Oct 28, 2013 #36 ughschool said: gsinθ - μkgcosθ = a? This is what it should be. So solve for μk now.
rock.freak667 Homework Helper Messages 6,221 Reaction score 31 Oct 28, 2013 #41 ughschool said: ugh wait no sorry gsinθ-a/gcosθ=uk? This is correct. So just substitute your values.