Finding Coefficients for Simple Partial Fraction Formula | Mathematica Help

  • Context: Graduate 
  • Thread starter Thread starter divB
  • Start date Start date
  • Tags Tags
    Fraction Partial
Click For Summary
SUMMARY

The discussion focuses on finding coefficients for a specific partial fraction formula using Mathematica. The user seeks to express the coefficients \(c_{m,n}\) in a form where the denominator contains \(z^{-1}\) exclusively. The solution involves using a change of variables to revert to the standard form, which can be achieved through the Apart function in Mathematica. This method is confirmed to be effective for obtaining the desired coefficient representation.

PREREQUISITES
  • Understanding of partial fraction decomposition
  • Familiarity with Mathematica, specifically the Apart function
  • Knowledge of complex variables and exponential functions
  • Basic skills in manipulating mathematical expressions
NEXT STEPS
  • Explore advanced features of the Apart function in Mathematica
  • Research change of variables techniques in mathematical analysis
  • Study partial fraction decomposition in the context of complex analysis
  • Learn about the application of exponential functions in control theory
USEFUL FOR

Mathematicians, engineers, and students working with partial fraction decomposition, particularly those utilizing Mathematica for complex variable analysis and control systems.

divB
Messages
85
Reaction score
0
Hi,

I found the following formula:

[tex] \prod_{m=1}^{N_d} \frac{1}{(1-e^{\alpha_{(m)}}z^{-1})^{n_{(m)}}} = \sum_{m=1}^{N_d} \sum_{n=1}^{n_{(m)}} \frac{c_{m,n} }{(1-e^{\alpha_{(m)}}z^{-1})^{n_{(m)}}}[/tex]

What I want is finding the coefficients [tex]c_{m,n}[/tex]. This looks like a simple partial fraction method.

In fact I am able to find the coefficients in the following form:

[tex]\dots = \sum_{m=1}^{N_d} \sum_{n=1}^{n_{(m)}} \frac{c_{m,n} }{(z-e^{\alpha_{(m)}})^{n_{(m)}}}[/tex]

using the standard partial fraction method. This is also what I get using Apart in Mathematica.

But I need the coefficients for the form described above: Only the denominator should contain [tex]z^{-1}[/tex] and nothing more.

Can anybody tell me how to get this form? Is it possible at all? (it should be because this formula is used in a paper...)

Is there any Mathematica command which produces the desired form?

Thank you very much.

Regards,
divB
 
Physics news on Phys.org
use a change of variables for the exponential and the 1/z, you would be back in the standard form again. Find the partial fractional form and replace the variables.
 
Oh, I am so stupid ... sure, this works!

Thank you very much!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
4K
Replies
12
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K