Finding complementary function from roots r=0,1 in variation of parameters

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s7b
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Hi,

When using the method of variation of parameters to solve something like;

y'' + y' = 2^x

I got the aux. equation: r^2 - r =0 which gives the roots r=0,1

How do I find the complementary equation yc?
 
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what is the aux. eqn? did you solve the homogenous eqn by assuming an exponential then differentiating and plugging in?
 
s7b said:
Hi,

When using the method of variation of parameters to solve something like;

y'' + y' = 2^x

I got the aux. equation: r^2 - r =0 which gives the roots r=0,1

How do I find the complementary equation yc?

If you meant complementary function then it got nothing to do with the method of variation of parameters. The method is meant for computing a particular solution yp(x).