Finding constants for 3 wave functions

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Homework Help Overview

The discussion revolves around finding constants for wave functions associated with vibrating molecules, specifically focusing on the ground, first excited, and second excited states. The wave functions are presented as part of an orthogonal set, and the task is to determine the constants d, e, and f.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of orthogonality conditions to derive constants, with attempts to integrate the wave functions to establish relationships between them. Questions arise regarding the validity of certain integrals and the implications of normalization.

Discussion Status

Some participants have provided guidance on the use of orthogonality, suggesting alternative integrals to explore. There is an ongoing examination of the integration process, with participants questioning the nature of specific functions involved in the calculations.

Contextual Notes

Participants are navigating the complexities of integrating functions over infinite limits and the implications of odd and even functions in relation to orthogonality. There is a noted focus on ensuring the correct application of normalization and orthogonality principles.

terp.asessed
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Homework Statement


The ground, 1st excited state and 2nd excited state wave functions for a vibrating molecules are:

Ψ0(x) = a e2/2
Ψ1(x) = b (x+d) e2/2
Ψ2(x) = c (x2 + ex + f) e2/2

respectively, with constants: a, b, c, d, e and f. Use the fact that these wave functions are part of an orthogonal set of functions to find out the constants, d, e and f ONLY.

Homework Equations


Given above

The Attempt at a Solution


I used these equations:
∫(from x = -infinite to +infinite) Ψ0 Ψ1 dx = 0 b/c of orthogonality--> from which I got d = 0
∫(from x = - infinite to + infinite) Ψ0 Ψ2 dx = 0 b/c of orthogonality--> from which I got f = -1/2α

...so, to solve for e, I decided to use ∫ (from x = -infinite to + infinite) Ψ2 Ψ2 dx = 1 (normalization)...except, I could not figure out how to get e:

c2∫(x2 + ex - 1/(2α))2e-αx2 dx = 1
∫(x2 + ex - 1/(2α))2e-αx2 dx = 1/c2
∫(x4 + 2ex3 -x2/α + e2x2 - ex/α +1/(4α2))e-αx2 = 1/c2
1/c2 = (3!)(1/2α)2(π/α)½ + 2e2 - 1/(2α)(π/α3)½ +e2/2 (π/α3)½ + 1/(4α2)(π/α)½

...and I am not sure if I doing right? If someone could point out the mistake or clarify, I would appreciate it!
 
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The normalization won't help you as this can be used to fix c only.
There is another orthogonality you can use.
 
Rly? No wonder I kept getting constant c value... Aside, could you expand on what you mean by:

mfb said:
There is another orthogonality you can use.

Do you mean ∫ψ1ψ2dx?
 
I am trying to integrate ∫ψ1ψ2dx:

∫ψ1ψ2dx = bc ∫xe-αx2 (x2+ex-1/2α) dx = 0
∫x3e-αx2 + e x2e-αx2 - xe-αx2/(2α) dx = 0

...I am having trouble integrating ∫ (x = -∞ to +∞) x3e-αx2 dx part--is this 0 or 1/α2?
 
Is the function x3e-αx2 odd or even?
 
terp.asessed said:
Do you mean ∫ψ1ψ2dx?
Sure, what else?
 

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