Finding Coordinates of Intersection in Parametric Forms

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Discussion Overview

The discussion revolves around finding the coordinates of intersection in parametric forms, particularly in the context of a problem involving parametric equations and planes. Participants seek clarification on the approach to solving these types of problems, indicating a focus on both theoretical understanding and practical application.

Discussion Character

  • Homework-related, Exploratory, Technical explanation

Main Points Raised

  • One participant expresses confusion regarding parametric forms and seeks help with specific questions they have encountered.
  • Another participant suggests using the equation of a plane to derive a parameter \( t \) from the given parametric equations.
  • There is a mention of parallel planes having the same attitude numbers, which is presented as a relevant consideration for the problem.
  • A further response reiterates the need to express \( x \), \( y \), and \( z \) in terms of \( t \) to facilitate solving the problem.

Areas of Agreement / Disagreement

Participants appear to be exploring the problem collaboratively, with some agreement on the methods to approach the solution, but no consensus on the specific steps or clarity of the concepts involved.

Contextual Notes

There are indications of missing assumptions regarding the definitions of the parameters and the specific equations of the planes involved, which may affect the clarity of the discussion.

TheFallen018
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Hey,

I have a couple of questions I've been doing online which have left me a little puzzled. The first one, I'm not really sure how to go about. I think a lot of that comes down to having not had a lot of experience with parametric forms.

I'll just post screenshots of where I'm up to on them, as they'll probably explain better where I'm up to.This is the one I'm having the most trouble with
View attachment 8080

This one, I've got most of the questions, but the last one is leaving me a little confused.

View attachment 8081

Any help would be amazing. Thanks :)
 

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$$x-5=y-3=\dfrac{z}{2}=t$$. Use the equation of the plane to get $$t$$.

Parallel planes have the same attitude numbers. So $$2x-2y+2z=D$$. Use the point to get $$D$$.
 
mrtwhs said:
$$x-5=y-3=\dfrac{z}{2}=t$$. Use the equation of the plane to get $$t$$.

Parallel planes have the same attitude numbers. So $$2x-2y+2z=D$$. Use the point to get $$D$$.

Hey man, I appreciate the help. I guess I'm still not very familiar with this sort of stuff. Would you be able to expand on that a little? Cheers
 
$$x-5=t$$, so $$x=$$ ? Do the same for $$y$$ and $$z$$.
 

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