The discussion revolves around determining the currents I1, I2, and I3 in a circuit using Kirchhoff's Laws, specifically focusing on the junction and loop rules. The problem involves internal resistance of batteries and requires careful application of circuit analysis principles.
Participants are actively engaging in refining the equations, with some providing constructive feedback on the original poster's attempts. There is a recognition of the need for consistency in labeling currents and their corresponding resistances, indicating a productive direction in the discussion.
Some participants note the importance of multiplying resistances by their respective currents to accurately reflect potential changes, highlighting a common point of confusion in applying Ohm's Law within the context of Kirchhoff's Loop Rule.
This looks good.Angie K. said:
How did you get these two equations?Angie K. said:
For one thing, you forgot to multiply the internal resistance by the current to get the voltage drop.Angie K. said:
I'm seeing a mix of voltage and resistance terms, some resistances multiplied by currents and some not. So as written those equations cannot be correct. You are summing potential changes around the loop, so any resistor value must be multiplied by a current in order to realize its potential change (Ohm's Law). Perhaps you could group the resistance terms for given currents in parentheses?Angie K. said:
Angie K. said:
Aren't 2.48 and 8 and 10 all resistances? What currents multiply them? I see only two voltage sources in the loop (both 12 V).
Again, I don't see currents multiplying each resistance.
Angie K. said: