(adsbygoogle = window.adsbygoogle || []).push({}); 1. From a lab experiment, I measured the volume of trapped air at various temperatures. I know I did calculations correctly up to the point that I drew the linear relationship between ln (p of H2O in atm) to 1/T (in Kelvin). My textbook says the slope of this graph is supposed to equal -ΔHvap/R, but the first thing that's confusing me is that I don't know what the units are and the second thing that's confusing me is just that the numbers don't work out. The slope of the line in this graph is -5158.73, but I don't understand how units fit into this. As I've said, the y-axis is ln (p of H2O in atm) and the x-axis is 1/T (in Kelvin).

2. I don't...know what to put in this section.

3. If the slope is equal to -ΔHvap/R, then...

-5158.73 = -ΔHvap/R

ΔHvap = 5158.73 * 0.08206 (Again, I have no idea where my units are!!)

ΔHvap = 423.3 *something*

I appreciate any help; thank you!

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# Finding ΔHvap of water from graph of ln (p of H2O in atm) versus 1/T

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