Finding distance based off acceleration

[JDR 007]

[SOLVED] finding distance based off acceleration

Homework Statement

A car slows down uniformly from a speed of 26.0 m/s to rest in 4.50 s. How far did it travel in that time?

Homework Equations

Acceleration (you all know it)

The Attempt at a Solution

I am totally stuck all I can do is find acceleration ...-5.78m/s^2

 

[learningphysics]

What kinematics formulas do you know for uniform acceleration? displacement formulas...

 

[Kurdt]

If you've found the acceleration, is there any other equation you know where you can work out the distance?

https://www.physicsforums.com/showpost.php?p=905663&postcount=2

 

[JDR 007]

$$x = x_0 + v_0 t + (1/2) a t^2$$ Should I try using this?

 

[learningphysics]

$$x = x_0 + v_0 t + (1/2) a t^2$$ Should I try using this?

you can do that since you've calculated acceleration.

you can also use $$d = \frac{(v1 + v2)}{2}*t$$

which also gives you the answer.

 

[JDR 007]

45.495m is that right?

 

[learningphysics]

45.495m is that right?

No. how did you get that?

 

[JDR 007]

I accidentally pluged accel. in for velocity

 

[JDR 007]

so.. 26*4.5-1/2(-5.78) what am I missing

 

[JDR 007]

58.5?...v1 26m/s v2 0m/s t=4.5

 

[Kurdt]

You should add on the acceleraton term and multiply it by the time squared.

 

[Kurdt]

58.5?...v1 26m/s v2 0m/s t=4.5

That is correct.

 

[JDR 007]

I totally was making that harder than it was, I would like to thank you for your help