Finding Maximum Velocity in Train Motion

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Homework Help Overview

The problem involves a train traveling a distance of 1.2 km with an average velocity of 43.2 km/h. The motion is characterized by three phases: acceleration, uniform motion, and deceleration, with specific time intervals provided for the first and last phases. The goal is to determine the maximum velocity of the train.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating the total time based on average velocity and distance, with one participant attempting to find the time spent in uniform motion. Questions arise about how to visualize the motion through a velocity-time graph.

Discussion Status

Some participants have suggested drawing a velocity-time graph to better understand the motion, while others are seeking clarification on how to construct such a graph using the known data. The discussion is ongoing, with various interpretations of the motion being explored.

Contextual Notes

There is an emphasis on understanding the relationship between distance, velocity, and time, as well as the significance of the area under the velocity-time graph. Participants are navigating the constraints of the problem setup and the provided information.

Vitalii
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Homework Statement


A train travels a distance of 1,2 km between two stations with an average velocity of 43.2 km/h. During it's motion, at the time t1=40s it moved accelerated, then at time t2 it moved uniformly, then at t3=40s it moved uniformly slowed. Find the maximum velocity of the train.
The acceleration during the slowed motion is equal in modulus to the acceleration during the accelerated motion.

distance=1,2 km
average velocity=43.2 km/h
t1=40s
t3=40s
|a3|= a1

Hopefully it makes sense.

Homework Equations



The Attempt at a Solution


I tried solving it by finding the total time. Ttotal=average velocity/total distance. 1.2/43.2=0.027 h or 97.2 seconds

from here i can find t2 which is 97.2-40-40=12.7
after this I'm stuck and don't know what to do next.
 
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Vitalii said:

Homework Statement


A train travels a distance of 1,2 km between two stations with an average velocity of 43.2 km/h. During it's motion, at the time t1=40s it moved accelerated, then at time t2 it moved uniformly, then at t3=40s it moved uniformly slowed. Find the maximum velocity of the train.
The acceleration during the slowed motion is equal in modulus to the acceleration during the accelerated motion.

distance=1,2 km
average velocity=43.2 km/h
t1=40s
t3=40s
|a3|= a1

Hopefully it makes sense.

Homework Equations



The Attempt at a Solution


I tried solving it by finding the total time. Ttotal=average velocity/total distance. 1.2/43.2=0.027 h or 97.2 seconds

from here i can find t2 which is 97.2-40-40=12.7
after this I'm stuck and don't know what to do next.

You could try drawing a graph of velocity against time.
 
PeroK said:
You could try drawing a graph of velocity against time.
How exactly can i draw a graph of velocity against time with all my known data?
 
Vitalii said:
How exactly can i draw a graph of velocity against time with all my known data?

What's the problem? It accelerates, it moves at constant speed for a time, then it decelerates to a stop. You can draw that.
 
PeroK said:
What's the problem? It accelerates, it moves at constant speed for a time, then it decelerates to a stop. You can draw that.
How do i draw a velocity against time graph?
 
Vitalii said:
How do i draw a velocity against time graph?

You put time along the x-axis and velocity along the y-axis, then you draw the velocity as a function of time.

You need to know that distance traveled is the area under the velocity-time graph.

Do they not teach you this anymore?
 

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