- #1
Vitalii
- 2
- 0
Homework Statement
A train travels a distance of 1,2 km between two stations with an average velocity of 43.2 km/h. During it's motion, at the time t1=40s it moved accelerated, then at time t2 it moved uniformly, then at t3=40s it moved uniformly slowed. Find the maximum velocity of the train.
The acceleration during the slowed motion is equal in modulus to the acceleration during the accelerated motion.
distance=1,2 km
average velocity=43.2 km/h
t1=40s
t3=40s
|a3|= a1
Hopefully it makes sense.
Homework Equations
The Attempt at a Solution
I tried solving it by finding the total time. Ttotal=average velocity/total distance. 1.2/43.2=0.027 h or 97.2 seconds
from here i can find t2 which is 97.2-40-40=12.7
after this I'm stuck and don't know what to do next.