Finding distance in a race based on speed

[bling-bling]

Homework Statement

You nose out another runner to win the 100.000 m dash. If your total time for the race was 11.800 s and you aced out the other runner by 0.001 s, by how many meters did you win?

Homework Equations

a = v-v0 / t

The Attempt at a Solution

So i found the acceleration of both the runners and took the difference between their accelerations. Now what do i do to find the distance the runner won by?
100 m / 11.801 s = 8.474 m/s
100 m /11.800 s = 8.475 m/s
8.475 m/s - 8.474 m/s = 0.001 m/s

 

[tiny-tim]

hi bling-bling!

So i found the acceleration of both the runners and took the difference between their accelerations. Now what do i do to find the distance the runner won by?
100 m / 11.801 s = 8.474 m/s
100 m /11.800 s = 8.475 m/s
8.475 m/s - 8.474 m/s = 0.001 m/s

(i think you mean "speed", not "acceleration" )

0.001 m/s is the relative speed, sooo … ?

(btw, won't you need more than 4 https://www.physicsforums.com/library.php?do=view_item&itemid=523" in your intermediate steps if you want reasonable accuracy after subtracting? )

 

[bling-bling]

so the 0.001 is not the distance that the runner won by? if not, how do i figure that out?