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Finding distance in a race based on speed

  1. Sep 6, 2011 #1
    1. The problem statement, all variables and given/known data
    You nose out another runner to win the 100.000 m dash. If your total time for the race was 11.800 s and you aced out the other runner by 0.001 s, by how many meters did you win?

    2. Relevant equations
    a = v-v0 / t


    3. The attempt at a solution
    So i found the acceleration of both the runners and took the difference between their accelerations. Now what do i do to find the distance the runner won by?
    100 m / 11.801 s = 8.474 m/s
    100 m /11.800 s = 8.475 m/s
    8.475 m/s - 8.474 m/s = 0.001 m/s
     
  2. jcsd
  3. Sep 7, 2011 #2

    tiny-tim

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    hi bling-bling! :smile:
    (i think you mean "speed", not "acceleration" :wink:)

    0.001 m/s is the relative speed, sooo … ? :smile:

    (btw, won't you need more than 4 https://www.physicsforums.com/library.php?do=view_item&itemid=523" in your intermediate steps if you want reasonable accuracy after subtracting? :wink:)
     
    Last edited by a moderator: Apr 26, 2017
  4. Sep 7, 2011 #3
    so the 0.001 is not the distance that the runner won by? if not, how do i figure that out?
     
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