1-D (I think) Speed to distance problem

  • Thread starter Thread starter magnanimousto
  • Start date Start date
  • Tags Tags
    Speed
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 1K views
magnanimousto
Messages
10
Reaction score
0

Homework Statement



A runner exerts a constant force to accelerate from rest to 2.0 m/s over a distance of 12 m.
Assuming the runner can keep up the same force, what total distance would be needed to ac-
celerate up from rest to 3.0 m/s?

Homework Equations



none given.

The Attempt at a Solution



The answer to the problem is 27. After quite some time spent thinking I tried solving first part for time using x= 1/2 vt and then plugging it into 2nd part. but that gives time as 12 and 2nd x as 18 so wrong. Dunno how to solve it
 
Physics news on Phys.org
magnanimousto said:

Homework Statement



A runner exerts a constant force to accelerate from rest to 2.0 m/s over a distance of 12 m.
Assuming the runner can keep up the same force, what total distance would be needed to ac-
celerate up from rest to 3.0 m/s?

Homework Equations



none given.

The Attempt at a Solution



The answer to the problem is 27. After quite some time spent thinking I tried solving first part for time using x= 1/2 vt and then plugging it into 2nd part. but that gives time as 12 and 2nd x as 18 so wrong. Dunno how to solve it
Hello magnanimousto. Welcome to PF!

What kinematic equations do you know?

Alternatively, do you know the Work-Energy Theorem ?
 
This is a constant acceleration problem, so you can use the basic kinematic equations for that case. Try solving for the acceleration first, and using that value for the next part.

If you don't know those equations, here's the one you should probably use -- they're very helpful to memorize though.
[itex]v_{f}^{2}= v_{i}^{2} + 2aΔd[/itex]
 
Thanks jackarms & SammyS.I do know kinematics equations, for some reason it never occurred to me that since the force is the same in both so must be the acceleration