Solving for Runner's Speed at End of Race | Physics Homework Help

  • Thread starter Thread starter jwang023
  • Start date Start date
  • Tags Tags
    Stuck
Click For Summary
SUMMARY

The runner accelerates at 1.7 m/s² for 4.8 seconds, resulting in a final speed at the end of the race. The calculation involves using the formula for final velocity under constant acceleration, which is v = u + at, where u is the initial velocity (0 m/s), a is the acceleration (1.7 m/s²), and t is the time (4.8 seconds). The final speed of the runner at the end of the race is 8.16 m/s, as the runner maintains this speed after acceleration ceases.

PREREQUISITES
  • Understanding of kinematic equations
  • Basic knowledge of acceleration and velocity
  • Familiarity with units of measurement in physics
  • Ability to perform basic arithmetic calculations
NEXT STEPS
  • Review kinematic equations for motion under constant acceleration
  • Explore the concept of instantaneous velocity
  • Study the effects of varying acceleration on final speed
  • Learn about real-world applications of acceleration in sports science
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators seeking to enhance their teaching methods in motion analysis.

jwang023
Messages
19
Reaction score
0

Homework Statement


I figured out the speed of the runner at t=2.0 seconds, but I am stuck on finding v of the runner at the end of the race.

Q: At the starting gun, a runner accelerates at 1.7 m/s^2 for 4.8 seconds. The runner's acceleration is zero for the rest of the race. what is the speed of the runner at the end of the race?


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
never mind! Figured it out!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
11
Views
7K
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
Replies
1
Views
2K