Finding Ek with force, mass, and time.

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SUMMARY

The discussion centers on calculating the kinetic energy of a 10kg box being pushed by a 10N force on a frictionless surface over 10 seconds. Using Newton's second law (F=ma), the acceleration is determined to be 1 m/s². This acceleration is then applied to find the final velocity (Vf) using the equation Vf=Vi+at, resulting in a final velocity of 10 m/s. The kinetic energy (Ek) is calculated using the formula Ek=0.5mv², yielding a final result of 500J, which is confirmed as accurate based on the distance traveled.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with kinematic equations (Vf=Vi+at)
  • Knowledge of kinetic energy formula (Ek=0.5mv²)
  • Basic concepts of motion on frictionless surfaces
NEXT STEPS
  • Review the principles of Newton's laws of motion
  • Study kinematic equations in-depth for various scenarios
  • Explore energy concepts, particularly kinetic and potential energy
  • Investigate real-world applications of frictionless motion in physics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of force, mass, and energy calculations.

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Homework Statement



A 10kg box at rest is being pushed on a frictionless surface by a force of 10N. The force is in the same direction as the motion of the box. 10 seconds later, how much kinetic energy will this box have?

Homework Equations



1. F=ma
2. Vf=Vi+at
3. Ek=0.5mv2

The Attempt at a Solution



I used formula 1 along with the F and mass to find the acceleration to be 1 m/s2. Then, I plugged that into formula 2, given an initial velocity of 0, acceleration of 1 m/s2, and a time of 10s. This gave me Vf at 10m/s. I used that in formula 3, with mass being 10kg. This gave me a final Ek of 500J.

Is this correct? 500J seems a little high but, I've no clue how else to do this. Thanks in advance.
 
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1J is the energy exerted by a force of 1N thaat moves an object by 1m. The force in this case is 10N and the distance is 50m(0.5at^2=100/2), so 500J seems fine.
 

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