Finding Equilibrium in a Hanging Beam System

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SUMMARY

The discussion focuses on a physics problem involving a 6.00-meter-long uniform beam in equilibrium, weighing 138 N, with an unknown weight at one end and a concrete block at the other. The beam is suspended at a point to the right of its center, creating an angle with the vertical. Participants seek clarification on the weight of the concrete block and the angle of the beam to solve for the unknown weight.

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Homework Statement



In the figure a 6.00-m-long, uniform beam is hanging from a point to the right of its center. The beam weighs 138 and makes an angle of with the vertical. At the right-hand end of the beam a concrete block weighing is hung; an unknown weight hangs at the other end.
If the system is in equilibrium, what is w ? You can ignore the thickness of the beam.

Homework Equations



F=ma

The Attempt at a Solution



i don't rly know where to start i just need a hint
 
Last edited:
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The beam weighs 138 and makes an angle of with the vertical

Does the beam weigh 138 kg? What is the angle that is made with the vertical?

At the right-hand end of the beam a concrete block weighing is hung

How much does this block weigh?
 

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