Calculating Forces on a Hanging Beam: Find Horizontal and Vertical Components

[krw1]

urgent help needed...I tried my best!~

I tried my best for hours and need help help?
thanks for any help you can now?


A uniform, 31.9 kg beam of length 3.00 m is hanging horizontally as shown in the diagram below. It is pinned to a vertical wall at point B and supported by a uniform 21.4 kg diagonal brace that is pinned at point C on the beam and at point A on the wall. [Use g = 9.81 m/s2.]

http://lewis.chem.sfu.ca/res/tccfl/jac/24_Statics/Graphics/beam-2.png

There is a load W, with a weight of 157 N, hanging at the end of the horizontal beam. The distance BC is 2.13 m, and the distance AB is 1.68 m. (The distance BD is 3.00 m.)
What is the vertical component of the force on the horizontal beam at joint C? (Use "+" if the force component is up, "-" if it is down.)
Cy = 441.5 N
Hint for doing the next part:
Unlike the situation with a massless support, the "tension" in the diagonal brace will not be at the same angle as the brace. The second step in doing this problem is to use the free-body diagram for the brace, along with the 3rd-law reaction force to Cy that acts downward on the brace, to solve for Cx.

What is the horizontal component of the force on the diagonal brace at joint C? (Use "+" if the force component is right, "-" if it is left.)
Cx = You must be careful to have the correct direction for every force that acts on the brace, and the correct lever arm for each of them, in your free-body diagram for the brace. Do you have Cy pointing down, opposite to its direction when it acts on the beam?


Find the horizontal and vertical components of the force on the horizontal beam at the joint B. Use "+" for forces up or to the right, "-" for forces down or to the left.
Bx =
By =

Find the horizontal and vertical components of the force on the diagonal brace at the joint A. Use "+" for forces up or to the right, "-" for forces down or to the left.
Ax =
Ay =

 

[berkeman]

Your diagram is not serving up. And you must show some of your "hours" of work in order for us to help you.

 

[kyle8921]

Hello and thank you for reaching out for help with your calculations. It seems like you are trying to find the horizontal and vertical components of the forces on a hanging beam. This can be a complex problem, so it's understandable that you may need some assistance.

First, it's important to make sure that you understand the given information and have a clear understanding of the problem. It may be helpful to draw a free-body diagram and label all the forces acting on the beam and the diagonal brace.

To find the vertical component of the force on the horizontal beam at joint C, you can use the equation Fy = mg, where Fy represents the vertical force, m is the mass of the beam, and g is the acceleration due to gravity. In this case, Fy = (31.9 kg)(9.81 m/s^2) = 313.239 N. Since the force is acting downwards, the vertical component would be negative, so Cy = -313.239 N.

To find the horizontal component of the force on the diagonal brace at joint C, you can use the equation Fx = F * cos(theta), where Fx represents the horizontal force, F is the total force on the brace, and theta is the angle between the brace and the horizontal beam. In this case, Fx = (157 N) * cos(45 degrees) = 111.004 N. Since the force is acting to the right, the horizontal component would be positive, so Cx = 111.004 N.

For the forces at joint B, you can use the same equations but with different values. The horizontal component (Bx) will be equal to the horizontal component of the force on the diagonal brace at joint C, as they are connected. The vertical component (By) will be equal to the vertical component of the force on the horizontal beam at joint C, as they are also connected.

For the forces at joint A, you can use the same equations but with different values. The horizontal component (Ax) will be equal to the horizontal component of the force on the diagonal brace at joint C, as they are connected. The vertical component (Ay) will be equal to the vertical component of the force on the diagonal brace at joint C, but with a negative sign, as the direction of the force on the brace will be opposite at joint A.

I hope this helps and good luck with your calculations! Remember to double check your free