a. A uniform beam is hanging from a poing 1.00 m to the right of its center. The beam weights 140 N and makes an angle of 30° with the vertical. At the right-hand end of the beam, a 100-N weight is hung; an unknown weight w hangs at the left end. If the system is in equilibrium, what is w? b. If the beam makes, instead, an angle of 45° with the vertical, what is w?
ετ = 0, T = IR
The Attempt at a Solution
w(4)(sin150°) - 100(2)(sin30°), but the w I'm getting is if the beam is balanced. How do I calculate it including an angle, so it's not perfectly horizontal? I can't think of an equation that relates the net torque with the change in angle.
Thank you for any help.