MHB Finding $f(1)$ in a Polynomial of Integer Coefficients $\leq$ 4

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The discussion revolves around finding the value of $f(1)$ for a polynomial $f(x)$ with integer coefficients less than 4, given that $f(4) = 2009$. Participants confirm that the polynomial's coefficients must be integers in the range of 0 to 3. The calculations reveal that the correct result for $f(1)$ is 11. The method used by a participant named kaliprasad is acknowledged as correct and effective. The focus remains on the polynomial's constraints and the derived values.
anemone
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Given $f(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0$, where $a_0, a_a,\cdots,a_n$ are all smaller than 4 and are integer, $a_n \in (0, 1, 2,\cdots)$.

Given that $f(4)=2009$, find $f(1)$.
 
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anemone said:
Given $f(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0$, where $a_0, a_a,\cdots,a_n$ are all smaller than 4 and are integer, $a_n \in (0, 1, 2,\cdots)$.

Given that $f(4)=2009$, find $f(1)$.

= 1 + 3 + 3 + 1 + 2 + 1 = 11

as f(x) = x^5 + 3x^4 + 3x^3 + x^2 +2x +1

as no coefficient is >4 and we are given f(4) subtract the highest power of 4 as many times as it can go

2009 = 1024 + 985
985 = 256 * 3 + 217
217 = 64 * 3 + 25
25 = 16 + 9
9 = 2 *4 + 1
 
kaliprasad said:
= 1 + 3 + 3 + 1 + 2 + 1 = 11

as f(x) = x^5 + 3x^4 + 3x^3 + x^2 +2x +1

as no coefficient is >4 and we are given f(4) subtract the highest power of 4 as many times as it can go

2009 = 1024 + 985
985 = 256 * 3 + 217
217 = 64 * 3 + 25
25 = 16 + 9
9 = 2 *4 + 1

Hey kaliprasad,

Thanks for participating and yes, the answer is correct and your method is great and nice!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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