Finding final velocity in a perfectly elastic collision

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SUMMARY

The final velocity of marble B in a perfectly elastic collision, where marble A has an initial velocity of 1.69 m/s and comes to rest, is 1.69 m/s. The conservation of momentum and kinetic energy principles confirm that the initial momentum (1.69 m/s) is transferred to marble B, resulting in its final velocity. The calculations provided in the discussion accurately demonstrate this outcome, affirming that marble B's final velocity equals marble A's initial velocity.

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  • Familiarity with basic algebra
  • Concept of initial and final velocities
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ilovedeathcab
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[solved] finding final velocity in a perfectly elastic collision

~~~Two marbles with equal masses collide. Marble A has an initial velocity of 1.69 m/s while marble B is initially at rest. If marble A comes to rest as a result of the initial collision, what is the final velocity of marble B?

* DO NOT include units in your answer.
* Give your answer with two decimals.
* Answers will be accepted if they are within 0.02 of the correct answer.

~Can anyone clarify this?
1. m1v1i + m2v2i = m1v1f + m2v2f

masses cancel...
2. v1i+v2i = v1f+v2f

3. (1.69m/s) + (0m/s) = (0m/s) + v2f

4. 1.69 m/s= v2f

I'm not sure this is correct...
 
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ilovedeathcab said:
~~~Two marbles with equal masses collide. Marble A has an initial velocity of 1.69 m/s while marble B is initially at rest. If marble A comes to rest as a result of the initial collision, what is the final velocity of marble B?

* DO NOT include units in your answer.
* Give your answer with two decimals.
* Answers will be accepted if they are within 0.02 of the correct answer.

~Can anyone clarify this?
1. m1v1i + m2v2i = m1v1f + m2v2f

masses cancel...
2. v1i+v2i = v1f+v2f

3. (1.69m/s) + (0m/s) = (0m/s) + v2f

4. 1.69 m/s= v2f

I'm not sure this is correct...

Looks correct.
 
thank you so much!
 

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