Finding Final Velocity in Momentum and Velocity Problems

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SUMMARY

The discussion focuses on calculating the final velocity of a railroad handcar after an object is thrown from it. The initial mass of the handcar and its contents is 160 kg, moving at 4.70 m/s. When a 28.0 kg object is thrown backward at the same velocity relative to the car, the final velocity of the handcar is determined to be 5.52 m/s. The correct application of the momentum equation, p=mv, is crucial for solving such problems accurately.

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Homework Statement



A railroad handcar is moving along straight, frictionless tracks with negligible air resistance. In the following cases, the car initially has a total mass (car and contents) of 160 kg and is traveling east with a velocity of magnitude 4.70 m/s. Find the final velocity of the car in each case, assuming that the handcar does not leave the tracks.

An object with a mass of 28.0 kg is thrown backward out of the car with a velocity of 4.70 m/s relative to the initial motion of the car.

Homework Equations



p=mv

The Attempt at a Solution



the momentum of the system is

p = (160+28)(4.7) = 883.6

so

883.6 = 160(vf) + 28(-4.7+4.7)

883.6 = 160vf

vf = 5.52 m/s

Where did i got wrong? :(

Thank you for any help
 
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The total mass of the cart is 160kg, so your total momentum would be 160*4.7.

After it is thrown out, it would lose 28 kg. So the final mass is 160-28.
 
Thank you :)

i was reading the question wrong haha i always seem to do that.
 

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