Finding Forces and Work in a Pulley System

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gunni91
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Homework Statement



Need some serious help with this one :O

A box with a weight WA hangs in pulleys ,(see figure 1). Find the force to pull A up with constant speed and calculate the work which the tractive force F produces ( with the movement of s) and also the work and tractive force T1 produce .
Pulleys and strings are frictionless and both without mass!.

Diagram of a three-pulley block and tackle hanging from a ceiling line, with a rope pulled down by force F over distance s and a weight W_A hanging from the lowest pulley, with tension T_1 and displacement s_1 marked.


Homework Equations






The Attempt at a Solution

 
gunni91 said:

Homework Statement



Need some serious help with this one :O

A box with a weight WA hangs in pulleys ,(see figure 1). Find the force to pull A up with constant speed and calculate the work which the tractive force F produces ( with the movement of s) and also the work and tractive force T1 produce .
Pulleys and strings are frictionless and both without mass!.

Diagram of a pulley system: three pulleys hang from a ceiling line, with a rope running from a force F at the left end down to a block labelled W_A at the bottom. Tension is marked T1 near the lowest pulley, and displacements s and s1 are shown by dashed arrows.


Homework Equations






The Attempt at a Solution


taikng tensions ,T1=4F
and taking constrained motion,
acc. of pulling end=4 times acc. of wA
differentiating that we get s=4s1
therefore work done by F=Fs
work done by T1=T1s1=4F x s/4=Fs

correct me if i m wrong,i just tried.
 
The result is correct. Balance of forces gives that WA=T1=4F. The question is the force needed to move the load with constant speed, so write out that F=WA/4.
The mass moves with constant speed so there is no acceleration. The constraints apply for the displacements and changes of length of the pieces of the ropes, but not for the non-existent accelerations. You can say that moving the end of the left rope by s will cause the other two pieces shorten by s/2 so the middle pulley raises by s/2. In the same way, raising the end of the right rope by s/2 lifts the right pulley by s/4.

ehild
 
sorry didn't see the name
properly,very sorry.thanks ehild!
 
ErwinMoses said:
sorry didn't see the name
properly,very sorry.thanks ehild!

You are welcome :smile:

ehild