Finding forces on a car rounding a curve

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SUMMARY

The discussion focuses on calculating the forces acting on a car with a mass of 1200 kg as it rounds a curve with a radius of 40 m at a speed of 15 m/s. Key calculations include the time to complete a half-circle turn, which is determined to be approximately 16.75 seconds, and the maximum static frictional force, calculated to be 6750 N. Additionally, the discussion addresses the acceleration required to reach 40 m/s and the banking angle needed to prevent skidding on a curve with a radius of 80 m. The correct banking angle is derived using the formula arctan(θ) = v²/(gR), resulting in an angle of approximately 1.11 radians.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with centripetal force calculations (mv²/r)
  • Knowledge of friction coefficients (static, rolling, kinetic)
  • Basic trigonometry for calculating angles (arctan function)
NEXT STEPS
  • Explore advanced friction dynamics in vehicle handling
  • Learn about centripetal acceleration and its applications
  • Research the effects of banking angles on vehicle stability
  • Study the relationship between speed, radius, and friction in circular motion
USEFUL FOR

Physics students, automotive engineers, and anyone interested in vehicle dynamics and the forces acting on cars during turns.

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Homework Statement


A car with mass of 1200kg turns sharply with a radius of 40m and at 15/ms. The tires have a static friction of 0.9, rolling at 0.6 and kinetic at 0.3.

1) how long does it take to make a turn at half a circle.
2) what is the magnitude of frictional force on the tires in the turn
3) After the turn, the car accelerates to 40m/s, assuming the divers uses max acceleration from friction, how long does it take to reach the new speed.
4) the driver takes another curve at 40 m/s with a radius of 80 and skids. the roads are banked. what angles does the road need to be banked to prevent skidding.

Homework Equations


F=ma
mv^2/r

The Attempt at a Solution



a) t=\frac{2\Pi R}{v}= \frac{2 Pi (40)}{15} so 16.75 seconds

b) F=ma
F_{smax}=1200\frac{v^2}{r}
F_{smax}=1200\frac{15^2}{40}
=6750N
c) have no clue how to do C...im not sure how to go about it...

D) arctan ∅= \frac{v^2}{gR}

arctan ∅ \frac{40^2}{-9.8m/s*80}

I get theta 1.11° degrees but that seems kindsa low.
 
Last edited:
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1/a: half a circle, not a full circle.
2/b: I agree
3/c: Given the coefficient of friction, what is the maximal horizontal force between car and ground?
4/d: Did you draw a sketch?

In general, keeping the units everywhere can help to spot mistakes.
 
baird.lindsay said:
arctan ∅ \frac{40^2}{-9.8m/s*80}
I get theta 1.11° degrees but that seems kindsa low.
No, 1.11 radians.
 

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