What is the magnitude of the force exerted by friction?

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Homework Help Overview

The problem involves a 600-kg car traveling at 30.0 m/s around a banked curve with a radius of 120 m and an angle of 25.0°. The coefficient of static friction between the tires and the road is given as 0.300. The main question is about determining the magnitude of the force exerted by friction on the car.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the equations of motion relevant to the scenario. There are questions about the correctness of the equations used and how to define static friction in this context. Some participants express confusion about creating a mathematical model that incorporates both static friction and centripetal acceleration.

Discussion Status

The discussion is ongoing, with some participants affirming the validity of the original equations while others suggest reconsidering the definition of static friction. There is a recognition of the need to balance the forces involved and to check if the static coefficient is sufficient to prevent sliding.

Contextual Notes

Participants note the importance of understanding the maximum ratio of frictional force to normal force and the implications of not having the kinetic coefficient provided. There is an acknowledgment that the problem may not lead to sliding, given the information available.

CStudy
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Homework Statement


Question: [/B]A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coefficient of static friction between the car's tires and the road is 0.300. What is the magnitude of the force exerted by friction on the car?

Homework Equations


F = ma

The Attempt at a Solution


http://imgur.com/FLrr1D6

Netwon 2nd Law Equations:
$$\sum F_{net, x} = nsin\theta +f_{s}cos\theta =m\frac{v^2}{r}$$
$$\sum F_{net, y}=ncos\theta -f_{s}sin\theta -mg =0$$
$$f_{s} = \mu n$$

Can anyone verify I am on the right track for solving the magnitude of the force exerted by friction. I have a feeling my equations maybe incorrect.

Here is the link to my diagram if it does not show. http://imgur.com/FLrr1D6
 
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Your equations look OK.
 
CStudy said:
##f_{s} = \mu_s n##
That is not quite right.
 
Any suggestions on how do define the static friction? Haruspex, what you have pointed out is the source of my confusion. I understand the the static friction combined with some of the normal force is the cause of the centripetal acceleration, but I am having difficulties creating a mathematical model.

Should I just ignored defining the static friction and just solve for the components? You think that would give me the correct answer.
 
CStudy said:
Any suggestions on how do define the static friction? Haruspex, what you have pointed out is the source of my confusion. I understand the the static friction combined with some of the normal force is the cause of the centripetal acceleration, but I am having difficulties creating a mathematical model.

Should I just ignored defining the static friction and just solve for the components? You think that would give me the correct answer.
I haven't done the calculation, but it probably would in the present case.
With static friction, it is important to remember the coefficient only tells you the maximum ratio of frictional force to normal force. If the surfaces are not sliding, the magnitude of the frictional force is anything up to ##\mu_sN##.

Logically, you should assume no sliding, determine the force from the other information, then check if the static coefficient is high enough. If not, it will slde, so you then calculate the frictional force using the kinetic coefficient. Since you are not told the kinetic coefficient, it is very likely that it will not slide.
 

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