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## Homework Statement

What is the minimum coefficient of friction needed between the tires and the ground so you make the turn safely?[/B]

**Car= 1394.7kg**

You=75kg

Radius of turn = 40m

Velocity = 20m/s

You=75kg

Radius of turn = 40m

Velocity = 20m/s

## Homework Equations

Fnet = MAc (Ac = centripetal Acceleration) = Force of friction

Force of Friction (Ff) = Mu(Fn) of Mu(mg)

MAc = (MV^2)/r[/B]

## The Attempt at a Solution

(MV^2)/r = Mu(Mg) mass cancels out and i solve for mu ==> mu = (V^2/rg)

mu = 20^2 / (40*9.8)= 1.02

If that is correct is it possible for the friction coefficient to be more than 1?