- #1
dizco29
- 32
- 0
hey guys, getting back into some basic algebra (so hope you don't mind a real newbie) and was doing a factoring tutorial on the web, and came across this.
The work for finding the GCF of three terms is shown below.
102k^5m^2
51k^4m
153k^2m^2
First find the GCF of the coefficients:
102 (1, 2, 3, 6, 17, 34, 51, 102)
51 (1, 3, 17, 51)
153 (1, 3, 9, 17, 51, 153)
GCF (of coefficients only) = 51
Next find the GCF of the variables:
k^5 m^2
k^4 m
k^2 m^2
GCF (of variables) = k2m
Now multiply the two GCFs
GCF of the entire term = 51k^2 m
what I don't understand is how the GCF for K is 2. Because 5 is not divisble by 2. So how can that be?
here's a link to the page if the above is not clear.
http://www.algebrahelp.com/lessons/f...indgcf/pg2.htm
Thanks!
The work for finding the GCF of three terms is shown below.
102k^5m^2
51k^4m
153k^2m^2
First find the GCF of the coefficients:
102 (1, 2, 3, 6, 17, 34, 51, 102)
51 (1, 3, 17, 51)
153 (1, 3, 9, 17, 51, 153)
GCF (of coefficients only) = 51
Next find the GCF of the variables:
k^5 m^2
k^4 m
k^2 m^2
GCF (of variables) = k2m
Now multiply the two GCFs
GCF of the entire term = 51k^2 m
what I don't understand is how the GCF for K is 2. Because 5 is not divisble by 2. So how can that be?
here's a link to the page if the above is not clear.
http://www.algebrahelp.com/lessons/f...indgcf/pg2.htm
Thanks!