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dapiridoob
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1. A spring of spring constant k is attached to a support at the bottom of a ramp that makes an angle θ with the horizontal. A block of inertia m is pressed against the free end of the spring until the spring is compressed a distance d from its relaxed length. Call this position A. The block is then released and moves up the ramp until coming to rest at position B. The surface is rough from position A for a distance 2d up the ramp, and over this distance the coefficient of kinetic friction for the two surfaces is μ . Friction is negligible elsewhere.2.
What is the distance from A to B? Suppose the values of μ, k, d, θ, and m are such that the spring fully extends, but the block never goes higher than 2d .
Express your answer in terms of some or all of the variables k, μ, m, d, and θ3. First I started by solving for the change in x.
I got to the point where deltax=v^2/( μgcos(θ)+gsin(θ)) through kinematics and force equations. I'm very certain that this equation is the correct way to find the distance a block moves up a ramp with friction. Then, I replaced delta x with 1/2k(2d)^2 and solved for d.
I ended up d=the square root of (2V^2/(( μgcos(θ)+gsin(θ))k))/2.
This answer does not seem to be correct and there seems to be a lapse in logic in how I'm going about this.
What is the distance from A to B? Suppose the values of μ, k, d, θ, and m are such that the spring fully extends, but the block never goes higher than 2d .
Express your answer in terms of some or all of the variables k, μ, m, d, and θ3. First I started by solving for the change in x.
I got to the point where deltax=v^2/( μgcos(θ)+gsin(θ)) through kinematics and force equations. I'm very certain that this equation is the correct way to find the distance a block moves up a ramp with friction. Then, I replaced delta x with 1/2k(2d)^2 and solved for d.
I ended up d=the square root of (2V^2/(( μgcos(θ)+gsin(θ))k))/2.
This answer does not seem to be correct and there seems to be a lapse in logic in how I'm going about this.